VOGONS


First post, by darrinh

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Hi all,
I was given a 486 motherboard recently. As far as I can tell its a American Megatrends Super Voyager s61 or very similar. It has a 486SX on board however several chips are missing. I can see that U33 -> U41 are cache ram. I don't know what U32 was (adjacent to U33) or what U30 or U31 were (pics attached) . Anybody know this board and what the missing chips are? I did find a manual (probably) for the board but it doesn't explain what the missing chips are (except the cache chips). One of the markings on the board says '486DX-II Series 61'

many thanks
Darrin

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Reply 2 of 8, by mkarcher

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U32 is part of the chipset that is sticker-branded as AMI. The question is thus about U30/U31/U33, I guess. U34-U41 is for dual-bank cache, and as they are 32-pin sockets, the board should support 512K cache at least, probably even 1M. 1M has 64K cache lines. The biggest 28-pin SRAMS only have 32K entries, so you would need a DIP32 socket for the tag. Except... if you split the tag into two 32Kx8 chips. Assuming that 1024kbit (128K x 8) hit the market earlier than 512kbit chips, building the tag from 2* 32K x 8 instead of wasting half a 128K x 8 chip would make a lot of sense.
U33, the DIP22 socket next to the data cache sockets would perfectly fit for a 64K x 1 RAM used as dirty indicator. Early 486 chipsets couldn't merge tag and dirty into the same chip.

You might want to do some continuity tests between the supposed address bits of the chip types I suggested to verify or reject that hypothesis.

Reply 3 of 8, by darrinh

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Thanks rmay635703 and mkarcher , I checked all the settings and installed memory and was able to power it on. The POST screen was very interesting however....

Frustratingly, I've not been able to find an image or information on what those missing chips are but U34-U41 are 28 pin sockets if I'm counting correctly and the board has a configuration switch that allows to switch between 64K and 256K (which ever is installed), so I guess they will be 28 pin srams ? U30/31 would be 32K x 8 22 pin ?

many thanks
Darrin

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Reply 4 of 8, by darrinh

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ok, I can see from the attached image of the VLB version of this board, it has the same dip switch config for 64K/256K settings. It has 8 x 28 pin sram (32k x 8?) and a CY7C164 (16k x 4) in what would be U33 on my board. I guess then U30/U31 32K x 8 22 pin dip instead of the single W24257AK in the pic?

thanks
Darrin

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Reply 5 of 8, by Robin4

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darrinh wrote on 2021-08-19, 00:14:

ok, I can see from the attached image of the VLB version of this board, it has the same dip switch config for 64K/256K settings. It has 8 x 28 pin sram (32k x 8?) and a CY7C164 (16k x 4) in what would be U33 on my board. I guess then U30/U31 32K x 8 22 pin dip instead of the single W24257AK in the pic?

thanks
Darrin

Most left IC is the TAG chip.. Most right is the cache
The smallest IC socket is for Dirty bit.

This is a example:

https://stason.org/TULARC/pc/motherboards/E/E … 386-UM-386.html

~ At least it can do black and white~

Reply 6 of 8, by darrinh

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Thanks to all, I have got this up and running, will see if i can get the cache ram, but in the meantime, yes, I went there! There is nothing like getting something running on original hardware though.

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Reply 7 of 8, by mkarcher

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darrinh wrote on 2021-08-18, 22:12:

Thanks rmay635703 and mkarcher , I checked all the settings and installed memory and was able to power it on. The POST screen was very interesting however....

Frustratingly, I've not been able to find an image or information on what those missing chips are but U34-U41 are 28 pin sockets if I'm counting correctly and the board has a configuration switch that allows to switch between 64K and 256K (which ever is installed), so I guess they will be 28 pin srams ? U30/31 would be 32K x 8 22 pin ?

Oops, I did a mistake in my reasoning here. I've seen that U34-U41 are composed of two sockets. As narrow 28-pin sockets are much more available than 32-pin sockets (especially today, you don't get narrow 32-pin sockets at all), I supposed that U34-U41 were composed of 2*16 pin, not 2*14 pin. So U34-U41 are definitely meant to take 32K*8 chips for 256K cache or 8K*8 chips for 64K cache, providing either 16K or 4K of cache lines, 16 bytes each.

U30/31/33 are all 22-pin sockets, so I take all previous guesses back and claim that this is the very common classic old 386/486 cache chip layout: All three chips are 16K x 4. Two of them (U30/U31) are used in combination as 8 tag bits, and from U33 only a single bit is used as dirty indicator.

On later boards, usually the two 16K x 4 chips are replaced a by sinlge 32K x 8 chip (only using half of the chip, but 16K x 8 chips didn't exist back then). This happens especially with chipsets that can combine the dirty bit into the tag bits, or mainboards that use the cache just used in write-through mode, or run it in an "assume always dirty" configuration. In that case, the whole 256KB cache setup needs only a single kind of memory chips. Later on, memory manufacturers started producing 16K x 8 chips, with pinout identical to 32K x 8 chips, but ignoring one bit. Chips by Aster and Winbond did ignore a different bit, though. That's why some newer mainboards have a jumper to choose between "Aster tag" and "Winbond tag".