OK, so if I am getting this right,
P = I x V and V = I x R, therefore substituting V / R for I we get:
P = V^2 / R
That means for any given speaker, the Voltage it will draw is:
V = SQRT ( P x R )
That means for a 4R 0.5W Speaker we will get:
V = SQRT ( 0.5 x 4) = 1.4V
Going back to the original formula:
P = I x V therefore 0.5W = I x 1.4, and I = 0,36A
Is this a high current draw for a speaker?
Because if we do the same for a 8R 0.25W speaker:
V = SQRT ( 0.25 x 😎 = 1.4V
P = I x V therefore 0.25W = I x 1.4, and I = 0,18A
So basically double the current for double the power, which makes sense?
In that case an 8R 0.5W speaker should also work:
V = SQRT ( 0.5 x 😎 = 2V
P = I x V therefore 0.5W = I x 2, and I = 0,25A
Which is more or less half way and looks reasonable as well?
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