Reply 20 of 27, by oerk
wrote:I have been thinking a bit about it the last couple of days, and I think that in order to get 3.6 volt, you need to build something with
resistors as "the cheapest" solution.
Nah... the resulting voltage would be dependent on the current draw. Use diodes (1N4001 for example) in series for a steady voltage drop.
One silicon diode drops the voltage by 0.7V, so if you're using 3 AA batteries: 4.5V - 0.7V = 3.8V -> I think you can get away with that.
Plus, this solution protects against polarity error AND recharging.