Hello folks i want to try to install Win98 i have a genuine Disc for that and although i found the tutorial hereGuide - Windows 95 on DOSBox 0.74

i had once almost close to installing it but then windows :something like this:

http://img35.imageshack.us/img35/7144/error1pn.png

So now i want to make a bigger flat hdd space somewhat like 1.5 GB, where i can copy all the contents of Win98 disc and then try again, so i had made a flat hdd like 1.4 GB and used MS-DOS boot disk to give a partition using fdisk: which i did but it would show only 492 MB in size and i am puzzled and as i had followed the tutorial , which described a formula and only to give the amount of cylinders: which i did while making the flat HDD.
Please this : http://www.dosbox.com/wiki/IMGMOUNT#Hard_disk_images

Please see the screenshots : what it would look like:

http://img832.imageshack.us/img832/1531/cimg1500mb.png

http://img259.imageshack.us/img259/5356/cimgafterfdisk.png

http://img835.imageshack.us/img835/8532/cimgsize.png

1Hard disk images
2The "-size" parameter (required to to create bootable hard disk images)
3
4Didn't understand the "512,63,16,142" part?
5
6All you really need to know is that the formula is always:
7
8-size 512,63,16,X

Hope now it is clear as to what i am trying to achieve, but fdisk doesn't show that amount of space and i had made a 900 MB disk where fdisk showed only 235 MB.
So where did i go wrong here, i am not able to assign the correct size for the image hdd i created, help out please.

I want to try my hands at installing WIN ME and WIN 2000 too.