debs3759 wrote on 2023-04-22, 18:03:
At most I'd expect about 6% increase. ((850/800) - 1) x 100. Basic math.
I don't know...
x = (800 + 50) / 100
Next, let's define a function f(t) as:
f(t) = (t + 1) * (t^2 + 1) * (t^4 + 1) * (t^8 + 1) * (t^16 + 1) * (t^32 + 1) * (t^64 + 1) * (t^128 + 1) * (t^256 + 1)
Now, let's evaluate f(x) and subtract 1:
f(x) - 1 = ((800 + 50) / 100 + 1) * (((800 + 50) / 100)^2 + 1) * (((800 + 50) / 100)^4 + 1) * (((800 + 50) / 100)^8 + 1) * (((800 + 50) / 100)^16 + 1) * (((800 + 50) / 100)^32 + 1) * (((800 + 50) / 100)^64 + 1) * (((800 + 50) / 100)^128 + 1) * (((800 + 50) / 100)^256 + 1) - 1
Now, let's simplify this expression by multiplying out the terms:
f(x) - 1 = ((850 / 100) * ((850 / 100)^2 + 1) * ((850 / 100)^4 + 1) * ((850 / 100)^8 + 1) * ((850 / 100)^16 + 1) * ((850 / 100)^32 + 1) * ((850 / 100)^64 + 1) * ((850 / 100)^128 + 1) * ((850 / 100)^256 + 1)) - 1
Simplifying further, we get:
f(x) - 1 = (850 / 100) * (850^2 / 10000 + 1) * (850^4 / 100000000 + 1) * (850^8 / 100000000000000 + 1) * (850^16 / 100000000000000000000 + 1) * (850^32 / 100000000000000000000000000000 + 1) * (850^64 / 100000000000000000000000000000000000000000000 + 1) * (850^128 / 100000000000000000000000000000000000000000000000000000000000000000 + 1) * (850^256 / 1000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000 + 1) - 1
If we evaluate this expression, we get:
f(x) - 1 = 4.5 * 10^30
Now, let's calculate the percentage increase of f(x) - 1 over f(0) - 1:
((f(x) - 1) / (f(0) - 1)) * 100% = ((4.5 * 10^30) / 1) * 100% = 4.5 * 10^32%
Therefore, we can say that 800 + 50 is a 50% increase over... something.
Basic math.
Now for some blitting from the back buffer.