First post, by cristy6100
Hello and a good day, after many years I finally got the time to get this bad boy up and running, was a new old stock PC, first boot since it was made, still with 12MB RAM, 256KB cache module, still new Quantum 1.2GB HDD, Pentium 133Mhz, gradually I will start to clean it and make it a retro Windows 95 machine for some nice throwbacks to the good old days.
I am familiar with most hardware from this era growing with it, but I totally skipped the whole Pentium/MMX generation instead I upgraded straight from 486 to Pentium II back then, so I am a bit unfamiliar with how and why HP wired 2 resistors in the VRM socket, and as to why is there no VRM header on this motherboard? As far as I remember it used to be either the MB had a onboard VRM to convert 5V to 3.3V, or as HP and other OEM's they had 3.3V directly from the PSU with a 6Pin header 3Pins for GND and 3 pins for 3.3V, now the problem is I want to upgrade the CPU to something faster, like a 200MHz MMX or 233Mhz MMX, these ones need 2.8V if I remember right and we used to plug a VRM module in the header, and here is where I am a bit at a loss, I can build a VRM module to convert 3.3V to 2.8V but I don't understand why are there 2 resistors in that header?
Searching on the forums it seems there are multiple revisions of this PC and motherboard, some with a header, some without.
It seems the resistors bridge 5V pin to VSS pin, and I don't understand why is this necessary? Having the 3.3V header from the PSU, what is the need for those 2 resistors?
Is it safe to remove them and add a VRM module for 2.8V?
I wish a good day to all of you and I appreciate all time and help with this
Christan